maths

[enric]

Which is the correct syntax for removing a 30% of a value:

damage *= 0,7; // don't work (the 0.7 is not accepted by BA)
damage = damage * 7 / 10 ; // don't work

damage = damage * 7;
damage = damage / 10; Then it works but should be a better way no?

[pipfromslitherine]

The script doesn't deal with precedence in the same way as regular C. The second approach is the recommended solution.

Cheers

Pip

[Amaris]

Why so complicated?

I think it works:
damage = damage % 70;

[enric]

Thank Amaris, this works in the way that BA accept it but, unfortunately the result is not the searched.

damage = damage * 7;
damage = damage / 10; Then it works but should be a better way no?

If damage value was initially 100, after calculations is 70.

in your example
damage = damage % 70;

gives as result 30.

if using:

damage = damage % 30;

the result is 10 ????

[Amaris]

Sorry I'm mistaken! I didn't have BA under hand when I wrote this stupidity thing.

The % operator is the remainder of the Euclidean division.

Therefore the solution:
damage = damage * 7;
damage = damage / 10;
is better...

edit: correction of a second very stupid thing...