The MF BG 24 Archer that was disrupted and fighting 3 BG's should have rolled only 1 dice instead of 2.
In the end as hilighted on the console log the
0]BG[7] Helot javelinmen was selected
[2] BG[7] already took an anarchy charge test this turn
[1] BG[7] Helot javelinmen melee attacks BG[24] Median bowmen
[2] BG[7] vs BG[24] combat -> quality re-rolls are enabled
[2] BG[7] melee combat dice no: 2 *1/2 => 1 die
[2] 2(LF vs no LF,frg) (base)
[2] *1/2(frg,SDrd,sdrd) BG[7]
[2] BG[24] melee combat dice no: 4 -2 *2/3 => 2 dice
[2] 4(most BG's are rolling 4 dice in combat) (base)
[2] -2(BG[7] supporting EBGs: BG[1],BG[8])
[2] *2/3(dis,Drd,drd) BG[24]
[2] BG[7]'s melee combat POA: = 0
[2] BG[24]'s melee combat POA: +1 = 1
[2] +1(better armor vs no HW,El,CH,ART,BW) BG[24] vs BG[7]
[2] BG[7] dice roll: [(6)5] (-1 POA [5,6]) => 1 hit..
[2] BG[24] dice roll: 2,1 (+1 POA [4,5,6]) => 0 hits..
[2] BG[7](1 hit) vs BG[24](0 hits) combat => attacker BG[7] wins
[2] BG[24] (defeated) lost 4.07% (41) strength
[2] BG[7] (winner) lost 0.19% (1) strength
[3] BG[24] must pass a melee combat CHT
[3] BG[24] CHT -> quality re-rolls are enabled
[3] BG[24] CHT test score: 2+6 -1 = 7 >= 7 => passed
[3] -1(dis,SDrd,sdrd) BG[24]
[1] BG[7] Helot javelinmen was deselected
Tks!
