Support Shooting by DISR unit

This forum is for any questions about the rules. Post here is you need feedback from the design team.

Moderators: philqw78, terrys, hammy, Slitherine Core, Field of Glory Moderators, Field of Glory Design

Post Reply
imanfasil
Staff Sergeant - Kavallerie
Staff Sergeant - Kavallerie
Posts: 315
Joined: Thu Apr 03, 2008 4:18 pm
Location: Texas

Support Shooting by DISR unit

Post by imanfasil »

If a unit is charged on a 2 base frontage and would normally be entitled to 4 Impact dice and 2 dice of support shooting... how many dice to do I get if DISR? Do I have 6 total dice and have to lose 2, or do I lose 1 in 3 Impact dice (1), and 1 in 3 SupShooting dice (0) and roll a total of 3 and 2?

I saw the FAQ said they are treated as normal... but it wasn't clear to me if they were dealt with as a total.

Thanks,
James
philqw78
Chief of Staff - Elite Maus
Chief of Staff - Elite Maus
Posts: 8842
Joined: Tue Feb 06, 2007 11:31 am
Location: Manchester

Post by philqw78 »

Ask Hammy, this is one thing he is good at explaining. But in your example one of each is lost. however, If only 1 front rank base was contacted it gets difficulter, but you would be left with 1 front and 1 shooting base.
phil
putting the arg into argumentative, except for the lists I check where there is no argument!
imanfasil
Staff Sergeant - Kavallerie
Staff Sergeant - Kavallerie
Posts: 315
Joined: Thu Apr 03, 2008 4:18 pm
Location: Texas

Post by imanfasil »

Thanks. I read an extended thread here on dice loss so I understand that... I just didn't recall a mention of Support shooting and didn't know if it was two separate pools of dice or one big pool when doing the reductions for DISR (or anything else).
philqw78
Chief of Staff - Elite Maus
Chief of Staff - Elite Maus
Posts: 8842
Joined: Tue Feb 06, 2007 11:31 am
Location: Manchester

Post by philqw78 »

Its one big pool, but then those on different POA are lost by proportion
phil
putting the arg into argumentative, except for the lists I check where there is no argument!
elysiumsolutions@fsmail.n
Senior Corporal - Ju 87G
Senior Corporal - Ju 87G
Posts: 93
Joined: Mon Jun 07, 2010 10:17 am

Post by elysiumsolutions@fsmail.n »

You have 6 dice and need to lose 2.

These are 4 dice who might in this example need 4s and 2 who need 5s.

Easiest thing to do when playing is put out the dice. Then lose 1 per 3.
Take 3 of the 4 dice to one side and lose 1 of these.
This leaves 1 dice needing a 4 and 2 dice needing a 5. As there are more dice needing a 5 you lose one of these.

Leaving 3 dice needing a 4 and 1 needing a 5.

Hope this helps.

Paul Longmore
Mehrunes
Master Sergeant - U-boat
Master Sergeant - U-boat
Posts: 517
Joined: Tue Jul 14, 2009 12:21 pm

Post by Mehrunes »

Or another approach: 3/1 is nearer to the the exact 2:1 of 2,67/1,33 ratio than 2/2.
Post Reply

Return to “Rules Questions”