Slitherine

Given following situation:
- BG A is fighting against BG X to its front at -POA, BG Y to its flank at no POA, and BG Z to its rear at no POA
- BG A is fragmented and down to 2 dices

The rules state that you should allocate a dice against every enemy BG as long as you have enough, which is not the case (2 dices vs. 3 enemy BGs).
The rules also state that you have to allocate a dice against every POA combination WHEN FIGHTING A SINGLE ENEMY BG, which is not the case since here the different POAs correspond to different enemy BGs.

Therefore:
a) BG A can allocate its 2 dices against BG Y and BG Z (both at no POA)
or
b) BG A must allocate a dice against BG X (at -POA) and can choose where to allocate the second dice at no POA (either to BG Y or BG Z)

I would say b), but since the rules are not explicit about what happens when the different POAs correspond to different enemy BGs, i'd like to have a confirmation.

Many thanks,
Xavier

Allocate against every POA.

You have 2 zero POA and a single minus POA

so 1 dice to the evens, whichever one of the 2 you wish, and one to the minus

So B

Going though these questions and re-reading the rules sure makes one see things that were missed the first 100 times around.

Page 94, 1st bullet top of page, last sentence says to allocate the LOST dice in proportion to the number of bases fighting each enemy BG, leaving 1 against each enemy BG if possible. So you started with 4 dice. You'd have to lose 1 die against the unit that you were fighting with 2 dice (2 bases). Then lose 1 die from one of the other 2 bases in combat. Sounds to me like it would be your choice. (But I've been wrong before)

The next bullet talks about allocating dice against a single BG that you are fighting at different POAs--not the case here.

This is another point that could use a little clarification as to author's intent.

bbotus wrote:Going though these questions and re-reading the rules sure makes one see things that were missed the first 100 times around.

Page 94, 1st bullet top of page, last sentence says to allocate the LOST dice in proportion to the number of bases fighting each enemy BG, leaving 1 against each enemy BG if possible. So you started with 4 dice. You'd have to lose 1 die against the unit that you were fighting with 2 dice (2 bases). Then lose 1 die from one of the other 2 bases in combat. Sounds to me like it would be your choice. (But I've been wrong before)

The next bullet talks about allocating dice against a single BG that you are fighting at different POAs--not the case here.

This is another point that could use a little clarification as to author's intent.

That's the point. My first impression was the same as Phil's, but the exact wording might allow a different interpretation, and I'm not sure what was the authors' intention.
My common sense tells me Phil is right and it's just a matter of re-writing the last bullet point to avoid misunderstandings, but my common sense must not necessarily be the same as the authors'...

The authors would need common sense for that

I personally think that Mr Brody did an excellent job with the rules. What disappoints me is that there is not a web site with his statements clarifying the inevitable misinterpretations that we come up with.

Through-out the rules he always gives each player discretion to make his own decision when there is a choice. If a unit is losing dice, it has a problem. I don't see why it can't try to fight as best as it possibly can.

xavier wrote:Given following situation:
- BG A is fighting against BG X to its front at -POA, BG Y to its flank at no POA, and BG Z to its rear at no POA
- BG A is fragmented and down to 2 dices

The rules state that you should allocate a dice against every enemy BG as long as you have enough, which is not the case (2 dices vs. 3 enemy BGs).
The rules also state that you have to allocate a dice against every POA combination WHEN FIGHTING A SINGLE ENEMY BG, which is not the case since here the different POAs correspond to different enemy BGs.

Therefore:
a) BG A can allocate its 2 dices against BG Y and BG Z (both at no POA)
or
b) BG A must allocate a dice against BG X (at -POA) and can choose where to allocate the second dice at no POA (either to BG Y or BG Z)

I would say b), but since the rules are not explicit about what happens when the different POAs correspond to different enemy BGs, i'd like to have a confirmation.

Many thanks,
Xavier

Hell, with that scenario who cares? They're dead men walking

bbotus wrote:I personally think that Mr Brody did an excellent job with the rules. What disappoints me is that there is not a web site with his statements clarifying the inevitable misinterpretations that we come up with.

Through-out the rules he always gives each player discretion to make his own decision when there is a choice. If a unit is losing dice, it has a problem. I don't see why it can't try to fight as best as it possibly can.

Who is Mr Brody?

dave_r wrote:Who is Mr Brody?

I believe its an Eskimo nicjname for Mr Brodrey-Scott

dave_r wrote:
Who is Mr Brody?

My apologies to Richard Bodley Scott, Simon Hall and Terry Shaw; the authors of Field of Glory