Slitherine

I have a question about LF shooting in two ranks in terrain. If in terrain, like woods for instance, where only one rank shooting is allowed, do LF only count the front rank bases to determine how many dice to shoot with? And if so, do they still reduce dice by getting one dice per two shooting? In other words, if an unit of bow-armed LF is shooting in the woods, arranged 3 wide x 2 deep, do they shoot with 1 die or with 3 dice?

Thanks

Peter C
Sword and Sandal Gaming Blog
http://swordandsandalgaming.blogspot.com/

Pretty sure they get just the one dice.

petedalby wrote:Pretty sure they get just the one dice.

Certainly how we played it last night. I had to go 4-2 formation to get 2 dice from the 4 front rank bases.

Isn't that exactly what "shooting in one rank means"? Just ignore the 2nd rank completely.

Mehrunes wrote:Isn't that exactly what "shooting in one rank means"? Just ignore the 2nd rank completely.

Yeah - I thought that was the case, but I just wanted to check if that was the way other people saw it also.

Thanks guys.

Peter C
Sword and Sandal Gaming Blog
http://swordandsandalgaming.blogspot.com/

petedalby wrote:Pretty sure they get just the one dice.

You haven't had your coffee yet. Or you are just being too polite.

I am absolutely sure they get 1 and 1/2 dice. Assuming no other shooters it is rounded down to 1.

Here is another twist on the question. Assume two BGs of heavy/medium foot backed by light foot side by side. A 2x2 BG of mounted charges them so that one base hits each foot BG. How many dice do the LF support shooters contribute? One dice per BG or one dice total (LF losing 1 dice per 2 bases)? And if the latter, which BG gets the hit credited to its total?

Marc

babyshark wrote:Here is another twist on the question. Assume two BGs of heavy/medium foot backed by light foot side by side. A 2x2 BG of mounted charges them so that one base hits each foot BG. How many dice do the LF support shooters contribute? One dice per BG or one dice total (LF losing 1 dice per 2 bases)? And if the latter, which BG gets the hit credited to its total?

Good one.
Well page 93-94 try to get to this, but doesn't quite.

hazelbark wrote:

babyshark wrote:Here is another twist on the question. Assume two BGs of heavy/medium foot backed by light foot side by side. A 2x2 BG of mounted charges them so that one base hits each foot BG. How many dice do the LF support shooters contribute? One dice per BG or one dice total (LF losing 1 dice per 2 bases)? And if the latter, which BG gets the hit credited to its total?

Good one.
Well page 93-94 try to get to this, but doesn't quite.

LF in the impact phase "Impact Phase Dice" get 1 dice per base and lose 1 dice per 2 dice.

Dice losses are reckoned separately for each battlegroup getting dice.

So each BG gets 1 LF dice and loses none as it does not have a full 2.

It's two bases LF shooting and as per p.93, 3rd bullet you add the bases before calculating the dice. So 2 LF bases will lose 1 per 2 and will have 1 dice. Shooter chooses which BG gets the dice.

lawrenceg wrote:Dice losses are reckoned separately for each battlegroup getting dice.

While your bottom line may be accurate. This point is not. The case of 2 disrupted 4 base LH bow units. They do not each fire with 2 dice. They fire combined with 3 dice.

Page 93 last bullet.

I believe that the mechanism is that for combat, dice loss is calculated separately for each BG. For shooting it is calculated per target. that's the difference between the two cases. Support shooting is calculated as for combat but using shooting factors.

Chris

Hmmm. And what about the case of the single, two base wide MF + LF BG each of whose front rank bases gets impacted by a separate BG of mounted? Which one of the mounted BGs gets the hit? Does the MF player choose?

Marc

Mehrunes wrote:It's two bases LF shooting and as per p.93, 3rd bullet you add the bases before calculating the dice. So 2 LF bases will lose 1 per 2 and will have 1 dice. Shooter chooses which BG gets the dice.

That only applies if it is "1 dice per X bases".

If you think that includes the case X=1, impact phase dice is still 1 dice per base.

Regardless of that, dice losses are by battlegroups, that is explicit in the bullet on page 94: "If a battlegroup..."

While impact phase shooting is IMO clear, this does leave the question of what to do with dice that are made up from bases of different BGs in the shooting phase. Presumably a BG with 1 and a "half" dice does not lose any. Then 2 BGs each of 3 LH, both disrupted, would still get 3 dice.

This might want looking at in v2.0

babyshark wrote:Hmmm. And what about the case of the single, two base wide MF + LF BG each of whose front rank bases gets impacted by a separate BG of mounted? Which one of the mounted BGs gets the hit? Does the MF player choose?

Marc

Yes owning player.

Or you are just being too polite.

I always try to be polite Dan

petedalby wrote:

Or you are just being too polite.

I always try to be polite Dan

Yeah, but we rattled ya the other day!

lawrenceg wrote: Then 2 BGs each of 3 LH, both disrupted, would still get 3 dice.

A single BG of 3 LH only gets one dice. 2 Steady BG of 3 LH could get 3 dice at a single target. If they are both disrupted they would get 2 dice.

Your quote is broken. It's from lawrenceg, not me.

philqw78 wrote:A single BG of 3 LH only gets one dice. 2 Steady BG of 3 LH could get 3 dice at a single target. If they are both disrupted they would get 2 dice.

That's how it ought to work, but it's not clear from the rules as written.