Slitherine

Posted: **Tue Jun 30, 2009 11:41 pm**

If you have 2 blocks of LH in 2x2 formation.
Each are Disrupted.
Now either BG shooting at a target independently will still shoot with 2 dice. (Lose 1 per 3, but only generate 2 so lose none).

Now if these 2 BG's combine shooting on a single target. Do they now generate 4 total dice from Disrupted BG's and thus lose 1 down to 3?

It appears that all references to accumulating or losing dice in shooting is PER Target not Per shooter.

Please let me know if I have this correct.

Thank You
Gino
SMAC

Posted: **Wed Jul 01, 2009 6:13 am**

Correct Gino

Shooting dice accumulate by target; combat dice by fighting BG.

Lots of good reasons for this, but time doesn't permit at present.

Si

Posted: **Wed Jul 01, 2009 10:09 am**

So, if 2 disrupted BG each of 4 bases LH, one a BG of Poor XBow and one a BG BG of Superior bow were shooting at LF.
They would have 1 dice at evens re-rolling 1's and 2 dice at minus re-rolling 6's. So would end up better off without the XBow shooting.

Is this right?

Posted: **Wed Jul 01, 2009 10:28 am**

philqw78 wrote:So, if 2 disrupted BG each of 4 bases LH, one a BG of Poor XBow and one a BG BG of Superior bow were shooting at LF.
They would have 1 dice at evens re-rolling 1's and 2 dice at minus re-rolling 6's. So would end up better off without the XBow shooting.

Is this right?

I make it roughly (probability of getting the given number of hits):

Code: Select all


hits     with XBow    without Xbow
3            .03               0
2            .22               .34
1            .50               .49

so you are better off with the crossbows unless you need 2 hits to cause a test.

Posted: **Wed Jul 01, 2009 12:29 pm**

Perhaps it simulates the special case of the superior bowmen being nervous about being hit by friendly fire from the incompetent croosbowmen near by.

Posted: **Wed Jul 01, 2009 1:11 pm**

So, if 2 disrupted BG each of 4 bases LH, one a BG of Poor XBow and one a BG BG of Superior bow were shooting at LF.
They would have 1 dice at evens re-rolling 1's and 2 dice at minus re-rolling 6's. So would end up better off without the XBow shooting.

So you have two dice at evens (re-rolling ones) and two dice at minus (re-rolling sixes)

You have to lose one dice from the above four. Why would you choose to lose one of the superior dice?

Posted: **Wed Jul 01, 2009 1:13 pm**

Because combined dice must use the worst POA and quality

Posted: **Wed Jul 01, 2009 3:31 pm**

philqw78 wrote:Because combined dice must use the worst POA and quality

But there are no combined dice in your example, only 2 superior bow dice and 2 poor crossbow ones.

If there were 3 bases of superior bow and 5 bases of poor crossbow then you would get 1 superior dice, 2 poor dice and 1 combined dice (which is effectively another poor one).

Posted: **Wed Jul 01, 2009 7:15 pm**

rogerg wrote:Perhaps it simulates the special case of the superior bowmen being nervous about being hit by friendly fire from the incompetent croosbowmen near by.

Somehow this reminds me of the warning on APDSFS ammo. It says "Not to be fired over friendly troops". Of course, the sabot ejects as it leaves the barrel and has to go somewhere so naturally it is a danger to friendly troops who may be in front of the tank. This isn't an issue with other ammunition... or if the troops in front of you happen to not be friendly.

I wonder if the instruction manual defines 'friendly'

Ian

Slitherine

Disrupted Shooters and loss of dice

Disrupted Shooters and loss of dice